Comments on: Brain Game. How to Become a Psychic

By: Murali Krishnan

Murali Krishnan — Wed, 10 Jun 2009 08:48:09 +0000

hi all,
I think the solution is simple.U r sure that there r 10 heads in the group na..
So separate 10 random coins to form a group.. and remaining 40 will be in another group.. So if there are x heads in 10grp there will b 10-x heads in 40grp..
ie, the no of tails in 10grp is equal to the no of heads in 40grp..
So if u flip all the coins in 10grp all the tails will become heads and finally now both groups have same number of heads..
This is a nice puzzle.. and im gonna post this in my blog
( muralizblog.wordpress.com ).. I think u can see some gud puzzles in my blog..
thanx for the author who posted this..

By: Aaron

Aaron — Thu, 06 Mar 2008 04:10:51 +0000

in probability’s sake,
the initial face of each coin is irrelevant.

In flipping a coin, the chance it’s a heads or tails is 50/50.

If you pick up a coin, flip it, then put it to your right, then pick up another coin, flip it, and put it to your left. by the end, you’ll should have an equal number of faced / tails coins in each pile.

Or do we need a more concrete solution?

By: Joseph Smith (StillUnashamed)

Joseph Smith (StillUnashamed) — Mon, 25 Feb 2008 15:13:53 +0000

Great puzzel. I drew a total blank then last night, in bed just before I went to sleep the answer hit me. Draw out 10 pennies to form one group, leaving 40 in the other group. Turn each of those 10 pennies over. The result will be an equal number of heads up pennies in each group.

By: Al Kinsley

Al Kinsley — Tue, 19 Feb 2008 22:00:23 +0000

Seperate the coins into two groups one of 40 the other of 10.

Turn all of the coins in the group of 10 over.

This will give you two groups with the same number of heads up.

By: Geniusbeauty.com

Geniusbeauty.com — Tue, 19 Feb 2008 20:50:09 +0000

Alberto, you may use only those 50 coins and no extra coins.

By: Alberto Beale

Alberto Beale — Tue, 19 Feb 2008 20:21:00 +0000

Solving the riddle is simple: You turned over ten random coins, but you did not specify that these coins were part of the 50 one cent coins in the table. Therefore all of your 50 coins are still tails up.

All you have to do is count 25 coins and separate them from the other 25 coins. You will now have two groups of 25 coins that are tails up. Turn over one coin from each group . Now you have one coin in each group that is heads up.
Now both groups have the same number of coins that are heads up.

Alberto Beale